Question

A rubber band has a spring

constant of 23.6 N/m. How far
must you stretch it to store 1.25 J
of PEe?
(Unit = m)
Enter

Answer 1

Given: Spring constant(k) = 23.6 N/m

Elastic potential energy(P) = 1.25J

To find: Extension(x)

Solution: We know that,

`P= (1)/(2)kx^(2)`

i.e.
`1.25 = (1)/(2)(23.6)x^(2)`

`x^(2) =0.1059`

`x = √(0.1059)`

`x = 0.3254 m`

The rubber band should be stretched 0.3254 m apart