Question

IM GIVING 50 POINTS!

A box contains 1 plain pencil and 3 pens. A second box contains 5 color pencils and 5 crayons. One item from each box is chosen at random. What is the probability that a pen from the first box and a crayon from the second box are selected. Write your answer as a fraction in the simplest form

Answer 1

There are 4 items in the first box and 10 items in the second box, so there are 4 x 10 = 40 possible combinations of one item from each box.

The probability of selecting a pen from the first box is 3/4, since 3 of the 4 items in the first box are pens. The probability of selecting a crayon from the second box is 5/10 or 1/2, since there are 5 crayons in the second box out of 10 total items.

To find the probability of selecting a pen from the first box and a crayon from the second box, we need to multiply the probabilities of the two events:

P(pen from first box and crayon from second box) = P(pen from first box) * P(crayon from second box)

P(pen from first box and crayon from second box) = (3/4) * (1/2)

P(pen from first box and crayon from second box) = 3/8

Therefore, the probability that a pen from the first box and a crayon from the second box are selected is 3/8.

Answer 2

The probability of selecting a pen from the first box is 3/4, and the probability of selecting a crayon from the second box is 5/10 or 1/2.

To find the probability of both events occurring together, we multiply the probabilities:

(3/4) × (1/2) = 3/8

Therefore, the probability of selecting a pen from the first box and a crayon from the second box is 3/8.

Explanation: