Question

If a normal distribution has a mean of 62 and a standard deviation of 12, what

is the z-score for a value of 86?
OA. 0.5
OB. 1.5
O C. 1
2
OD.

Answer 1

The z-score is calculated as follows:

z = (x - μ) / σ

where x is the value of interest, μ is the mean, and σ is the standard deviation.

Plugging in the values given, we get:

z = (86 - 62) / 12 = 2

Therefore, the z-score for a value of 86 is 2.

The answer is (C) 2.

Explanation: