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The ph of a 0. 15-m solution of hso4−hso4− is 1. 43. Determine ka for hso4−hso4− from these data

User Stan Hurks
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The pH of a solution is related to the concentration of H+ ions in the solution by the following equation:

pH = -log[H+]

where [H+] is the concentration of H+ ions in moles per liter (M).

For the acid H2SO4, the dissociation can be written as follows:

H2SO4 ⇌ H+ + HSO4-

The acid dissociation constant, Ka, is defined as:

Ka = [H+][HSO4-]/[H2SO4]

Rearranging this equation gives:

[H+][HSO4-] = Ka[H2SO4]

Since the solution contains HSO4- ions, we can assume that all of the H2SO4 has dissociated, and therefore [H2SO4] = 0.15 M. We can also calculate the concentration of H+ ions using the pH:

pH = -log[H+]

10^(-pH) = [H+]

10^(-1.43) = [H+]

[H+] = 3.56 × 10^(-2) M

Substituting these values into the equation for Ka gives:

(3.56 × 10^(-2))(x) = Ka(0.15)

where x is the concentration of HSO4- ions. Solving for Ka:

Ka = (3.56 × 10^(-2))(0.15)/x

Ka = 5.34 × 10^(-3)/x

Therefore, the value of Ka depends on the concentration of HSO4- ions, which was not given in the problem. Without additional information, we cannot calculate the value of Ka.

User Michel Ayres
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