Question

A snack-size bag of M&Ms candies contains 14 red candies, 14 blue, 9 green, 15 brown, 3 orange, and 8 yellow. If a candy is randomly picked from the bag, compute the following.

Answer 1

Answer: The probability of picking a red candy is 14/63, the probability of picking a blue candy is 14/63, the probability of picking a green candy is 9/63, the probability of picking a brown candy is 15/63, the probability of picking an orange candy is 3/63, and the probability of picking a yellow candy is 8/63. These probabilities can be calculated by dividing the number of candies of each color by the total number of candies in the bag.

Explanation:

Answer 2

Answer: vvvvv

Explanation:

The odds of getting a green M&M can be calculated by dividing the number of green M&M candies by the total number of candies in the bag.

Number of green M&Ms = 9

Total number of candies = 14 + 14 + 9 + 15 + 3 + 8 = 63

Odds of getting a green M&M = Number of green M&Ms / Total number of candies

Odds of getting a green M&M = 9/63 = 1/7

The probability of getting a green M&M can be calculated by dividing the number of green M&M candies by the total number of candies in the bag.

Probability of getting a green M&M = Number of green M&Ms / Total number of candies

Probability of getting a green M&M = 9/63 = 0.14285714285714285 or approximately 14.29% (rounded to two decimal places).

Also thanks a lot, now i want m&m's