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21 votes
21 votes
If (5x – 1) is a factor of 10x2 + bx + 7, what is the value of b? (

User Yeimy
by
3.2k points

1 Answer

11 votes
11 votes

Answer:

b = -37

Explanation:

Given that (5x -1) is one factor of the polynomial 10x² +bx +7, you want to know the value of b.

Solution

Let the factors of the polynomial be (5x -1) and (cx -d). Then the product is ...

(5x -1)(cx -d) = 5cx² -(c+5d) +d ≡ 10x² +bx +7

Equating coefficients, we find ...

5c = 10 ⇒ c = 2 . . . . . . . coefficient of x²

d = 7 . . . . . . . . . . . . . . . constant term

Then ...

b = -(c +5d) = -(2 +5(7)) = -37

The value of b is -37.

User Nimrod Dayan
by
3.3k points
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