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assuming you used 0.3g benzil, 0.5g dibenzyl ketone. which is the limiting reagent? what is the theoretical yield for this reaction? (please show calculations)

User Eneskaya
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Answer: The reaction between benzil and dibenzyl ketone to form 1,2-dibenzylidenecyclohexanone is:

2 C14H12O + NaOEt → C20H18O + H2O + NaOAc

The molar mass of benzil is 210.25 g/mol, and the molar mass of dibenzyl ketone is 234.30 g/mol. Using the given masses of each reactant, we can calculate the number of moles of each:

moles of benzil = 0.3 g / 210.25 g/mol = 0.001426 mol

moles of dibenzyl ketone = 0.5 g / 234.30 g/mol = 0.002133 mol

Based on the balanced equation, the stoichiometric ratio between benzil and dibenzyl ketone is 1:1, meaning they react in a 1:1 ratio. Since the number of moles of benzil is less than the number of moles of dibenzyl ketone, benzil is the limiting reagent.

To find the theoretical yield of the product, we need to determine the amount of the limiting reagent that reacts. Since benzil is the limiting reagent and reacts in a 1:1 ratio with dibenzyl ketone, the moles of product formed will also be equal to 0.001426 mol.

The molar mass of the product is 286.37 g/mol. Using the moles of product, we can calculate the theoretical yield:

theoretical yield = 0.001426 mol x 286.37 g/mol = 0.408 g or 408 mg

Therefore, the theoretical yield for this reaction is 0.408 g or 408 mg.

User Pandu
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