Question

Write the standard equation of the circle centered at (2, -3), which passes through (3, 5).

Answer 1

Explanation:

the standard equation for the circle is:

(x-a)²+(y-b)² = r²

the center is : A(a,b) and ridus r

you have : a= 2 and b= - 3 r²= (3-2)²+(5+3)²= 1+ 64

r² 65

the standard equation for the circle is:

(x-2)²+(y²+3 )=65