Answer: we can conclude that Parking Lot A is more expensive than Parking Lot B for 10 hours of parking, since Parking Lot A would cost $42.20 for 10 hours (using the equation we found below), while Parking Lot B would only cost $35.
Step-by-step explanation: To compare the cost of parking in the two different lots, we need to use the given information to determine the cost for a given amount of time parked in each lot.
For Parking Lot A, we can use the given data to create a table of time and cost pairs:
Time (hours) Cost (dollars)
2 10.60
7 21.20
12 37.10
Note that we can use the given pairs of time and cost to determine a function that relates the two variables. A linear function is a good choice here, since the cost appears to increase at a constant rate over time. Using the two given data points (2, 10.60) and (7, 21.20), we can find the slope of the line:
slope = (21.20 - 10.60) / (7 - 2) = 2.12
Using this slope and one of the data points, we can find the y-intercept of the line:
y - 10.60 = 2.12(x - 2)
y - 10.60 = 2.12x - 4.24
y = 2.12x + 6.36
This equation represents the cost of parking in Parking Lot A as a function of time parked.
For Parking Lot B, we can use the given graph to estimate the cost for a given amount of time parked. From the graph, we can see that the cost for parking 10 hours in Parking Lot B is about $35.
Therefore, we can conclude that Parking Lot A is more expensive than Parking Lot B for 10 hours of parking, since Parking Lot A would cost $42.20 for 10 hours (using the equation we found above), while Parking Lot B would only cost $35.