Question

Determine the limiting reactant and how much of that limiting reactant you would need in order to use up all of the non-limiting reactant.

Assume you have 25 grams of glucose and 40 grams of oxygen as reactants for the following photosynthesis reaction:
C6​H12​O6​ O + 6O2​ --> 6CO2​ + 6H2​O + Energy

A
Glucose is the limiting reactant; You would need .1388 moles of glucose to use up all of the Oxygen
B
Glucose is the limiting reactant; You would need .208 moles of glucose to use up all of the Oxygen
C
Oxygen is the limiting reactant; You would need 1.25 moles of Oxygen to use up all of the glucose
D
Oxygen is the limiting reactant; You would need .8328 moles of Oxygen to use up all of the glucose

Answer 1

B. Glucose is the limiting reactant you would need .207 moles of glucose