Question

THIS IS VERY LATE HELP PLEASE

Answer 1

Option A:

A. Each side of 5√x = 10 should be squared.

(5√x)^2 = 10^2

25x = 100, so x = 4

B. x = -6 is an extraneous solution, so x = 2 is the only solution. When solving equations with radicals, you need to check for extraneous solutions.

Option B:

`√(2x) + 5 = 1`

does not have any real solutions.

`\sqrt[4]{m + 4} - \sqrt[4]{3m} = 0`

`\sqrt[4]{m + 4} = \sqrt[4]{3m}`

`m + 4 = 3m`

`2m = 4`

`m = 2`