Answer:
As the circuit is connected for a long time, the current through the capacitor is 0. Thus the 1Ωand 4Ωresistance is in series. Also, the 2Ωand 8Ωresistance is in series.
Let the current be divided as I1=I2+I3 As the circuit is connected for a long time, the current through the capacitor is 0. Thus the 1Ωand 4Ωresistance is in series.
RC circuit-charge on capacitor after a "long time" Circuit: 10V goes to 100ohm resistor, then there's a branch point. One side leads to a a resistor R2 = 100ohms and the other to a capacitor with C = 1uF. The switch is located just before R1, and is closed for a long time.
an ideal capacitor is usually defined by: After a long time, when the capacitor is saturated with charge (as you said), we have 5V across the capacitor due to potential division between the two resistors (or applying ohms law to a resistor, if you like). So the charge on the capacitor is 5V * 1uF.
Step-by-step explanation: