Answer:
Explanation:
||y + 6|| = 10
Next, we can consider the two possible cases:
Case 1: y + 6 ≥ 0
If y + 6 is non-negative, then the absolute value of y + 6 is just y + 6 itself. So we have:
y + 6 = 10
y = 4
Case 2: y + 6 < 0
If y + 6 is negative, then the absolute value of y + 6 is the opposite of y + 6, which is -(y + 6). So we have:
-(y + 6) = 10
y + 6 = -10
y = -16
Therefore, the solutions to the equation 3||y + 6|| = 30 are y = 4 and y = -16.