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Expand.
your answer should be a polynomial in standard form
(9h+3)(-h-1)=

1 Answer

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Expanding (9h+3)(-h-1), we can use the distributive property of multiplication to multiply each term in the first factor by each term in the second factor:

(9h+3)(-h-1) = -9h^2 -9h -3h -3

Combining like terms, we get:

(9h+3)(-h-1) = -9h^2 -12h - 3

Therefore, the expanded form of the expression (9h+3)(-h-1) is -9h^2 -12h - 3, which is a polynomial in standard form.
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