Question

The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statistics include n = 681 drowning deaths of children with 30% of them attributable to beaches.

3.01

2.85

–3.01

–2.85

Answer 1

To test the claim, we need to conduct a hypothesis test with the null hypothesis being that the proportion of drowning deaths of children attributable to beaches is 0.25 and the alternative hypothesis being that it is more than 0.25.

Using a one-sample z-test with a significance level of 0.05, we can calculate the test statistic as:

z = (0.3 - 0.25) / sqrt(0.25 * 0.75 / 681) = 3.01

Since the alternative hypothesis is that the proportion is greater than 0.25, we need to find the area to the right of the test statistic in the standard normal distribution.

Using a standard normal table or calculator, we can find the p-value to be approximately 0.0013.

Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that there is sufficient evidence to support the claim that the proportion of drowning deaths of children attributable to beaches is more than 0.25.

Therefore, the answer is 3.01.