Question

The temperature of a sample of water increases from 22.5°C to 85.7°C. It absorbs

7540 J of heat. The mass of the water is
3.51g
119g
28.5g
0.0351g

Answer 1

We can answer this question using the formula: q=mcΔT

q = heat (joules, J)

m = mass (g)

c = specific heat capacity (J/g°C)

ΔT = change in temperature (temp final - temp initial) in °C

Specific heat capacity: the amount of energy required to increase the temperature of 1 g of an object by 1°C

• the specific heat capacity of water is 4.18 J/g°C

Using the information and isolating for m:

q = 28.5 g