Question

22. A rock is thrown straight up with an initial velocity of 24.5 m/s. What maximum height will the rock reach before starting to fall downward? (Take acceleration due to gravity as 9.80 m/s².)

a. 9.80 m
b. 19.6 m
c. 24.5 m
d. 30.6 m​

Answer 1

Answer:

(d) 30.6 m

Step-by-step explanation:

We can use the kinematic equation to find the maximum height reached by the rock:

vf^2 = vi^2 + 2ad

where vf is the final velocity (which is zero at the maximum height), vi is the initial velocity, a is the acceleration due to gravity, and d is the displacement (the maximum height reached).

Substituting the given values, we get:

0 = (24.5 m/s)^2 + 2(-9.80 m/s^2)d

Solving for d, we get:

d = (24.5 m/s)^2 / (2 × 9.80 m/s^2)
= 30.6 m

Therefore, the maximum height reached by the rock before starting to fall downward is 30.6 m.

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