Question

Please Help! Please show all work, will really appreciate it.

Answer 1

22487.9N

Step-by-step explanation:

Any two objects of sufficient mass experience a gravitational pull or force between them that is dependant on their masses and how far away they are from each other. The formula for the gravitational force between two objects is:

`F=G(m_(1) m_(2) )/(r^(2) )`

where F is the gravitational force, G is the gravitational constant (equal to 6.67x
`10^(-11)`),
`m_(1)` and
`m_(2)` are the masses of the two objects and r is the distance between their centres.

We know the satellite is 5400m above the earth surface, but we need to know the distance between their centres, not between their surfaces. To do this, we usually add the radius of each object to the distance between their surfaces, but since the satellite's radius is likely so small that it's negligible, we can just add Earth's radius, which is 6,371 km:

5400+6371000=6376400m

We know the value fo G because it's a constant, we are given the masses of the earth and the satellite (5.97x
`10^(24)`kg and 2300kg respectively), and we now know the distance between their centres (6376400m). Now we can sub these values into our formula to find the gravitational force:

`F=G(m_(1) m_(2) )/(r^(2) )`

`F=(6.67*10^(-11) )((2300) (5.96*10^(24) ) )/(6376400^(2) )`=22487.89596N

Answer 2

m1 * m2) / r^2)

Where F is the gravitational force, G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between them.

In this case, the mass of the satellite is 2300 kg and the mass of Earth is 5.97 x 1024 kg. The distance between the satellite and Earth's surface is 5400 m.

Plugging these values into the formula, we get:

F = (6.67 x 10^-11 N*m^2/kg^2) * ((2300 kg * (5.97 x 1024 kg)) / (5400 m)^2)

F = (6.67 x 10^-11 N*m^2/kg^2) * ((136510000000000 kg^2) / (291600 m^2))

F = 3.34 x 10^-4 N

Therefore, the gravitational force between the satellite and Earth is approximately 3.34 x 10^-4 N.