Question

A 10,000-ohm resistor is placed in series with a 100-ohm resistor. The current in the 10,000-ohm resistor is 10 A. If the resistors are swapped, how much current flows through the 100-ohm resistor?

Answer 1

approximately 9.901 A

Step-by-step explanation:

According to Ohm's law, the current in a circuit is directly proportional to the voltage and inversely proportional to the resistance. In this problem, we are given the resistance and the current in the 10,000-ohm resistor, but we need to calculate the current in the 100-ohm resistor.

First, we can use Ohm's law to calculate the voltage across the 10,000-ohm resistor:

V = IR = (10 A)(10,000 Ω) = 100,000 V

Since the two resistors are in series, the total resistance is:

R_total = R1 + R2 = 10,000 Ω + 100 Ω = 10,100 Ω

We can use Ohm's law again to find the current in the circuit:

I = V / R_total = 100,000 V / 10,100 Ω ≈ 9.901 A

When the resistors are swapped, the 100-ohm resistor becomes the 10,000-ohm resistor, and the 10,000-ohm resistor becomes the 100-ohm resistor. Since the total resistance is the same, the current through the circuit will be the same:

I = V / R_total = 100,000 V / 10,100 Ω ≈ 9.901 A

Therefore, the current through the 100-ohm resistor is approximately 9.901 A when the resistors are swapped.