Question

Write the equation of the circle below, with the center at (3, 1) and passing through the point (-3,4)

Answer 1

Explanation:

formula:

(x-h)²+(y-k)²=r² (h,k) is the center, you will have to calculate the r

r=
`\sqrt{(3-(-3))^(2) +(1-4)^(2) }`

=
`√(36+9)`

=
`√(45)` keep this as a square root, you will square it anyway

(x-3)² + (y-1)² =
`(√(45) )^(2)`

(x-3)² + (y-1)² = 45