Question

Two charged particles exert an electrostatic force of 36 N on each other. What will the magnitude of the force be if the distance between the two particles is increased to twice the original distance?

Answer 1

F= 14(36 N)= 9N

Explanation:

If the magnitude of the two charges is doubled and the distance between them is also doubled, then the force between the charges will be: 2P. P/2

Formula to calculate the magnitude of electrostatic force, we can use the equation E = k | Q | r 2 E = k | Q | r 2 to find the magnitude of the electric field.

The direction of the electric field is determined by the sign of the charge, which is negative in this case.

Coulomb's law calculates the magnitude of the force F between two point charges, q1, and q2, separated by a distance r. F=k|q1q2|r2.

F= 14(36 N)= 9N