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Solve the following quadratic equation for all values of x in simplest form.

Solve the following quadratic equation for all values of x in simplest form.-example-1
User Neil P
by
7.8k points

2 Answers

2 votes

Answer:

The answer is -9,-5

Explanation:

4(x+7)²+17=33

4(x+7)(x+7)+17=33

4[x²+7x+7x+49]+17=33

4(x²+14x+49)+17=33

4x²+56x+196+17-33=0

4x²+56x+180=0

divide althrough by 4

x²+14x+45=0

factorising

x²+9x+5x+45=0

x(x+9)+5(x+9)=0

(x+9)(x+5)=0

(x+9)=0,(x+5)=0

x= -9,x= -5

User MAP
by
8.3k points
7 votes

Answer:

x = - 9, x = - 5

Explanation:

4(x + 7)² + 17 = 33 ( subtract 17 from both sides )

4(x + 7)² = 16 ( divide both sides by 4 )

(x + 7)² = 4 ( take square root of both sides )

x + 7 = ±
√(4) = ± 2 ( subtract 7 from both sides )

x = - 7 ± 2

then

x = - 7 - 2 = - 9

x = - 7 + 2 = - 5

User Jameh
by
7.9k points