Question

The coordinates of the vertices of DEF are D(2,3), E(4,0), and F(1,−2). The coordinates of the vertices of TVW are T(0,3), V(−2,0), and W(1,−2).

Answer 1

are reflection across the y-axis and translation 2 units right.

Explanation:

Answer 2

To find the equation of the line containing the segment DE, we can use the coordinates of D and E to find the slope:

slope = (change in y) / (change in x) = (0 - 3) / (4 - 2) = -3/2

We can use the point-slope form of the equation of a line, using either D or E as the point:

y - 3 = (-3/2)(x - 2)

Simplifying this equation, we get:

y = (-3/2)x + 6

Similarly, to find the equation of the line containing the segment EF, we can find the slope using the coordinates of E and F:

slope = (change in y) / (change in x) = (-2 - 0) / (1 - 4) = 2/3

Using either E or F as the point, we can write the equation in point-slope form:

y - 0 = (2/3)(x - 4)

Simplifying, we get:

y = (2/3)x - (8/3)

To find the equation of the line containing the segment TV, we can find the slope using the coordinates of T and V:

slope = (change in y) / (change in x) = (0 - 3) / (-2 - 0) = 3/2

Using either T or V as the point, we can write the equation in point-slope form:

y - 3 = (3/2)(x - 0)

Simplifying, we get:

y = (3/2)x + 3

Finally, to find the equation of the line containing the segment VW, we can find the slope using the coordinates of V and W:

slope = (change in y) / (change in x) = (-2 - 0) / (1 - (-2)) = -2/3

Using either V or W as the point, we can write the equation in point-slope form:

y - 0 = (-2/3)(x - (-2))

Simplifying, we get:

y = (-2/3)x + (4/3)