Question

5. What is the value of x to the nearest tenth? The figure is not drawn to scale.

Answer 1

5.46

Explanation:

Using pythagoras theorem;

AD^2 = 5.3^2 - 4.1^2

AD^2 = 28.09-16.81

AD^2 = 11.28

AD = √11.28

AD = 3.36

x^2 = 3.36^2+4.3^2

x^2 = 11.28 + 18.49

x^2 = 29.77

x = 5.46

Hence the value of x is 5.46