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Questions are Below!!!

Questions are Below!!!-example-1

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Explanation:

Question 1 :

The statement that best describes the solutions of a two-variable equation is (1) The ordered pairs must lie on the graphed equation. This means that any ordered pair (x,y) that satisfies the equation will corresponds to a point on the graph of the equation. In other words, if we plot all the points (x,y) that make the equation true, we will obtain the graph of the equation. Any points that do not lie on the graph is not a solution to the equation. Therefore, when solving a two-variable equation, we need to find the values of x and y that make the equation true and plot those points on the graph to visualize the solutions.

Question 2 :

To use the arithmetic sequence formula, we need to know the first term (a1), the common difference (d), and the desired term (an). In this case, we are given the first term as 4 and the common difference as 3 (since each term is increasing by 3). To find the 10th term, we would replace the variable "n" with 10 in the formula. Therefore, to determine the 10th term of this sequence, we would use the formula:

a10 = a1 + (n-1)d

a10 = 4 + (10-1)*3

a10 = 4 + 27

a10 = 31

Thus, the 10th term of the given sequence is 31.

Question 3 :

The formula an = al + (n-1)d is used to determine the nth term in an arithmetic sequence, where "a" represents the first term in the sequence, "n" represents the term number being solved for, and "d" is the common difference between terms. The formula essentially states that to find any term in an arithmetic sequence, one must add the common difference between terms multiplied by the number of terms-1 to the value of the first term. This formula can be applied to various situations, such as determining the total cost of goods sold in a business with a constant markup percentage, or calculating the number of days it will take to save a given amount of money with a fixed monthly contribution. By understanding the principles behind the formula, individuals can successfully solve problems involving arithmetic sequences in a variety of contexts.

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