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My current grade is a 64.21%

7%-enrichment assignments
16%-homework assignments
19%-exam 1,2 and 3
20%-final exam
I have exam 3 next week, before final exam I want to up my grade to a 70% or above what grade would I need to get on my exam 3 to do so?

User Makela
by
8.1k points

2 Answers

3 votes

Answer:

i would say at least a 70

and i hope you do well

hope this helps ;)

User Stackular
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2 votes
To calculate the grade you need on Exam 3 to reach a 70% or higher, you can use the following formula:

(0.07 x enrichment assignments grade) + (0.16 x homework assignments grade) + (0.19 x Exam 1 grade) + (0.19 x Exam 2 grade) + (0.19 x Exam 3 grade) + (0.20 x Final exam grade) = 0.70 x total grade

Since you want to know what grade you need on Exam 3 specifically, you can rearrange the formula to isolate for Exam 3:

Exam 3 grade = (0.70 x total grade - 0.07 x enrichment assignments grade - 0.16 x homework assignments grade - 0.19 x Exam 1 grade - 0.19 x Exam 2 grade - 0.20 x Final exam grade) / 0.19

Plugging in your current grades, we get:

Exam 3 grade = (0.70 x 100 - 0.07 x 64.21 - 0.16 x ? - 0.19 x ? - 0.19 x ? - 0.20 x ?) / 0.19

Since we don't have your grades for Homework assignments, Exam 1, Exam 2, and Final exam, we'll use variables instead. Let's call them:

H = homework assignments grade
E1 = Exam 1 grade
E2 = Exam 2 grade
F = Final exam grade

Substituting these variables, we get:

Exam 3 grade = (0.70 x 100 - 0.07 x 64.21 - 0.16 x H - 0.19 x E1 - 0.19 x E2 - 0.20 x F) / 0.19

Simplifying:

Exam 3 grade = (7 - 0.44947 - 0.16H - 0.19E1 - 0.19E2 - 0.20F) / 0.19

Exam 3 grade = (6.55053 - 0.16H - 0.19E1 - 0.19E2 - 0.20F) / 0.19

Now, let's say you want to achieve a minimum grade of 70%. In other words, you want your total grade to be at least 70%. Using the same formula, we get:

(0.07 x enrichment assignments grade) + (0.16 x homework assignments grade) + (0.19 x Exam 1 grade) + (0.19 x Exam 2 grade) + (0.19 x Exam 3 grade) + (0.20 x Final exam grade) = 0.70 x 100

Simplifying:

0.07 x enrichment assignments grade + 0.16H + 0.19E1 + 0.19E2 + 0.19 x Exam 3 grade + 0.20F = 70

Substituting the expression we derived earlier for Exam 3 grade:

0.07 x enrichment assignments grade + 0.16H + 0.19E1 + 0.19E2 + (6.55053 - 0.16H - 0.19E1 - 0.19E2 - 0.20F) / 0.19 + 0.20F = 70

Simplifying:

0.07 x enrichment assignments grade + 1.01005 - 1.05263H - 1.01053E1 - 1
User Daniel Lyons
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