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Solve the inequality for the variable: 2(3c + 15) + 4c > 100

2 Answers

6 votes

Hello !

Answer:


\boxed

Explanation:

We are looking for the values of c that satisfy the following inequality :


\sf 2(3c + 15) + 4c > 100

Let's expand the left side of the inequality.


\sf 2* 3c +2* 15+4c > 100\\6c+30+4c > 100

Now we will combine like terms :


\sf 10c+30 > 100

Let's substract 30 from both sides of the inequality.


\sf 10c+30-30 > 100-30\\10c > 70

Finally, let's divide both sides by 10.

10>0 so the inequality remains the same.


\sf(10c)/(10) > (70)/(10) \\\boxed{\sf c > 7}

Have a nice day ;)

User Renanleandrof
by
8.6k points
5 votes

Answer:

c > 7

Explanation:

Now we have to,

→ Find the required value of c.

The equation is,

→ 2(3c + 15) + 4c > 100

Then the value of c will be,

→ 2(3c + 15) + 4c > 100

Applying Distributive property:

→ 2(3c) + 2(15) + 4c > 100

→ 6c + 30 + 4c > 100

Combining the like terms:

→ 10c + 30 > 100

→ 10c > 100 - 30

→ 10c > 70

Dividing the value 70 with 10:

→ c > 70 ÷ 10

→ [ c > 7 ]

Hence, the answer is c > 7.

User Xilliam
by
8.3k points

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