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Determine the solutions to the equation x^2 = 4x + 41.

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Answer:

The solutions to the equation x^2 = 4x + 41 are x = 2 + 2sqrt(11) and x = 2 - 2sqrt(11).

Explanation:

To solve the equation x^2 = 4x + 41, we can first rearrange it as x^2 - 4x - 41 = 0.

Next, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation. In this case, a = 1, b = -4, and c = -41.

Substituting these values into the formula, we get:

x = (4 ± sqrt((-4)^2 - 4(1)(-41))) / 2(1)

Simplifying:

x = (4 ± sqrt(176)) / 2

x = (4 ± 4sqrt(11)) / 2

x = 2 ± 2sqrt(11)

Therefore, the solutions to the equation x^2 = 4x + 41 are x = 2 + 2sqrt(11) and x = 2 - 2sqrt(11).

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