○=> Correct option :
Diameter of circle P is the same length as the radius of circle Q.
○=> Steps to derive correct option :
Given :
Diameter of circle P = 26 cm
Radius of circle P :
![=\tt (diameter)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/c1ffllzat384pgb8nybpb6cqglh921qqeb.png)
![= \tt (26)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ga39cyhq3wfjrrfsww4haebzlsy8eitmb2.png)
![\color{plum} = \tt13 \: cm](https://img.qammunity.org/2022/formulas/mathematics/high-school/90fn05rbtsz2a0s346h9ety147527xvp6y.png)
Thus, radius of circle P = 13 cm
Diameter of circle Q = 52 cm
Radius of circle Q :
![= \tt (diameter)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/rxrjnwy07d72l2zvvkwv3c0vyvkrtcp1qa.png)
![=\tt (52)/(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/zz5xcdp3v0z3irbb13a29l5ycso726m6at.png)
![\color{plum}= \tt26 \: cm](https://img.qammunity.org/2022/formulas/mathematics/high-school/5riehxycodbhmgpyc1tn7pvigjjt94wtc3.png)
Thus, radius of circle Q = 26 cm
Radius of circle R = 52 cm
Diameter of circle R :
![=\tt radius * 2](https://img.qammunity.org/2022/formulas/mathematics/high-school/dp04tp7gshn2xperjynwtg2vngh9vbw8m6.png)
![=\tt 52 * 2](https://img.qammunity.org/2022/formulas/mathematics/high-school/4zryed2vvml8gwfts46iy0met2g78k3w1v.png)
![\color{plum} = \tt104 \: cm](https://img.qammunity.org/2022/formulas/mathematics/high-school/sv1nso85xvt4jwsoksh07t50czvjiluqwc.png)
Thus, the diameter of circle R = 104 cm
☆ Conclusion :
▪︎Diameter of circle P is the same length as the radius of circle Q.
Therefore, the correct option is (C) Diameter of circle P is the same length as the radius of circle Q.