Question

Solve the triangle
A
B
C

Answer 1

The sum of the three interior angles is 180°
So; 180-58-41

A= 81°

Using law of sines to find side b and c; A-S-A

a/sinA = b/sinB = c/sinC Given side a= 10

10/sin(81°) = b/sin(58°) = c/sin(41°)

First side b;

10/sin(81°) b/sin(58°)

b= 10sin(58°) / sin(81°)

side b = 8.6

side c

10/sin(81°) c/sin(41°)

c= 10sin41° / sin81°

side c= 6.6