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Determine number of kilocalories a person in china ate each day in 1960

Determine number of kilocalories a person in china ate each day in 1960-example-1

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Answer:


1611 \text{ kilocalories}

Explanation:

During 1960, x = 0 because x represents the years since 1960, and no years have passed since 1960.

So, to solve for g(x) (kilocalories eaten) during 1960, all we have to do is plug 0 in for x on the right side of the equation and simplify:


g(x) = 1611(1.013)^0


g(x) = 1611(1)


\boxed{g(x) = 1611 \text{ kilocalories}}

Remember that anything to the power of 0 is 1.

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