Question

A. If you had 55.7 grams of N2and 13.8g of H2, which reactant would be limiting?

Answer 1

N2

Step-by-step explanation:

First you must balance the reaction.

N2 + H2 = NH3

N2 + 3H2 = 2NH3

Then find the moles of each:

55.7 g N2 x (1 mol / 28.02g) = 2.0 mol N2

13.8 g H2 x (1 mol / 2.016 g) = 6.8 mol H2

Convert both to moles of NH3

1 mol N2 : 2 mol NH3 so 4.0 mol NH3

3 mol H2 : 2 mol NH3 so 6.8 x 2/3 = 4.6 mol.

Therefore the lower one, N2 is limiting as it produces less moles.