The reaction between 4-chloro-1-butanol and sodium hydride results in a cyclization reaction, forming a cyclic compound.
The reaction between 4-chloro-1-butanol and sodium hydride results in a cyclization reaction.
In this reaction, the hydroxyl group (-OH) present in 4-chloro-1-butanol reacts with the sodium hydride to form a cyclic compound.
The reaction can be represented as follows:
4-chloro-1-butanol + sodium hydride → cyclic product
This cyclization reaction occurs due to the ability of the hydroxyl group to act as a nucleophile, attacking the electrophilic carbon atom in the 4-chloro-1-butanol molecule.
The resulting cyclic compound may have different functional groups depending on the specific reaction conditions.
The probable question may be:
when 4-chloro-1-butanol is placed in sodium hydride, a cyclization reaction occurs then which compound does it formed?