Question

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degrees celsius . During the reaction 69.0kJ of heat flows out of the bath and into the flask.Calculate the new temperature of the water bath.

Answer 1

Answer: The new temperature of the water bath is
`31.9^0C`

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

`Q=m* c* \Delta T`

Q = Heat released by water =
`69.0kJ=69000J` (1kJ=1000J)

m= mass of water = 8.10 kg= 8100 g (1kg=1000g)

c = specific heat capacity =
`4.184J/g^0C`

Initial temperature of the water =
`T_i` =
`33.9^0C`

Final temperature of the water =
`T_f` = ?

Change in temperature ,
`\Delta T=T_f-T_i`

Putting in the values, we get:

`-69000J=8100g* 4.184J/g^0C* (T_f-33.9)^0C`

`T_f=31.9^0C`

The new temperature of the water bath is
`31.9^0C`