Answer:
We can use the Ideal Gas Law to solve for the volume of the carbon dioxide gas:
PV = nRT
where:
P = pressure = 1.4 atm
V = volume = ?
n = moles = 0.6 mol
R = gas constant = 0.08206 L·atm/(mol·K)
T = temperature = 37 + 273 = 310 K
We rearrange the equation to solve for V:
V = (nRT) / P
Substituting the given values, we get:
V = (0.6 mol x 0.08206 L·atm/(mol·K) x 310 K) / 1.4 atm
V = 10.5 L
Therefore, there would be 10.5 liters in a 0.6 mol sample of carbon dioxide at 37 °C and 1.4 atm.