24.0k views
3 votes
A 2000kg vehicle travelling 30m/s takes 10s to stop. what force did the vehicle experience? show your work.

User Nick Kahn
by
9.2k points

1 Answer

3 votes

Step-by-step explanation:

The WORK required to stop the truck is equal to the initial Kinetic Energy of the truck ( 1/2 m v^2)

1/2 mv^2 = 1/2 * 2000 * 30^2 = 900 000 J

Distance travelled in 10 seconds is

d = vot - 1/2 at^2 where a = 30 m/s / 10 s = 3 m/s^2

= 30 (10) - 1/2 ( 3)(10^2) = 150 meters

Work = F * d

900 000 = F * 150

F = 6000 N

User Weike
by
8.4k points