Question

To approach the runway, a small plane must begin a 9 degree descent starting from a height of 1629 feet above the ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach?

PLS help

Answer 1

The answer to your problem is, 7192 feet

Explanation:

The height of the plane from the ground is given as:

H = 1125 ft

Here let say the distance is " d ". ( D = Distance )

Which is:

`(H)/(d) sin`θ

Then, d =
`(H)/(sin0)`

We will have:

d =
`(1125)/(sin9)`

d = 7192 feet

Thus the answer to your problem is, 7192 feet