Question

To how much water should 200. mL of 18 M sulfuric acid be added to prepare a 3.5 M solution

Answer 1

1.03L

Step-by-step explanation:

M1V1=M2V2

0.200L×18M=3.5M×V1

3.6=3.5M×V1

divide both sides by 3.5M to cancel out on the right

3.6÷3.5M=1.028L