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3 votes
Solve for y
A)115º
B)108º
C)90º
D)130º

Solve for y A)115º B)108º C)90º D)130º-example-1
User Paniclater
by
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1 Answer

4 votes

Answer:


\large\boxed{\tt y = 115^(\circ).}

Explanation:


\textsf{We are asked to find the measure of} \ \tt \angle Y.


\textsf{We are given a shape, but we aren't given what shape it is.}


\large\underline{\textsf{What is a Shape?}}


\textsf{A Shape is a specific outline sometimes dependent of how many sides it has.}


\underline{\textsf{Shapes that depend on outlines;}}


  • \textsf{Non-Polygons,}

  • \textsf{Shapes that aren't quadrilaterals,}

  • \textsf{Any shapes that are not classified under something.}


\underline{\textsf{Shapes that depend on the number of sides;}}


\textsf{Mainly the opposite.}


  • \textsf{Polygons,}

  • \textsf{Quadrilaterals,}

  • \textsf{Any shapes that are classified under something.}


\textsf{Because our shape has 5 sides, it's dependent on the amount of sides it has, which}


\textsf{makes the shape a Polygon.}


\large\underline{\textsf{What is a Polygon?}}


\textsf{A Polygon is a closed shape that classifies as a;}


  • \textsf{Triangle, or any shape with 3 sides,}

  • \textsf{Square/Rectangle, or any shape with 4 sides,}

  • \textsf{Pentagon, or any shape with 5 sides,}

  • \textsf{Hexagon, or any shape with 6 sides,}

  • \textsf{Heptagon, or any shape with 7 sides,}

  • \textsf{Octagon, or any shape with 8 sides,}

  • \textsf{Nonagon, or any shape with 9 sides,}

  • \textsf{Decagon, or any shape with 10 sides.}


\textsf{The list goes on forever.}


\textsf{Our shape is a Pentagon, due to the shape having 5 sides.}


\large\underline{\textsf{What is a Pentagon made up of?}}


\textsf{A Pentagon is a polygon that has 5 sides, meaning that it has 5 angles.}


\textsf{The total of the angles is what we should find out with a pattern.}


\underline{\textsf{What is the total of all the angles' measures of a Pentagon?}}


\textsf{A Triangle has 3 sides with 3 angles, which add up to 180}^(\circ).


\textsf{A Quadrilateral has 4 sides with 4 angles, which add up to 360}^(\circ).


\textsf{The Pattern is that when an extra side is added, the total measure of the angles}


\textsf{increase by 180}^(\circ).


\textsf{A Pentagon has 5 sides with 5 angles, which add up to} \ \boxed{\tt 540^(\circ).}


\textsf{Now that we know the total, we can form an equation.}


\tt 540^(\circ) = 135^(\circ) + 112^(\circ) + 88^(\circ) + y^(\circ) + 90^(\circ)


\textsf{Remember that Right Angles are 90}^(\circ) \ \textsf{angles that are represented with a box}


\textsf{symbol.}


\large\underline{\textsf{Solving;}}


\textsf{Now that we have our equation, we should \underline{combine like terms}, then use the}


\textsf{\underline{subtraction rule of equality} to find the measure of y.}


\underline{\textsf{Combine Like Terms;}}


\tt 540^(\circ) = \boxed{135^(\circ)} + \boxed{112^(\circ)} + \boxed{88^(\circ)} + y^(\circ) + \boxed{90^(\circ)}


\tt 540^(\circ) = 425^(\circ) + y^(\circ)


\underline{\textsf{Use the Subtraction Rule of Equality;}}


\tt 540^(\circ) - 425^(\circ) = 425^(\circ) - 425^(\circ)+ y^(\circ)


\large\boxed{\tt y = 115^(\circ).}

User Kebabman
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