Answer:
2.67 x 10^-4 M & 8.85 x 10^-8 M
Step-by-step explanation:
The minimum concentration of the precipitating agent required to cause precipitation of the cation from the solution can be determined using the solubility product constant (Ksp) of the salt that would be formed. The Ksp is an equilibrium constant that represents the maximum amount of solid that can dissolve in water to form a saturated solution.
For part a, calcium iodide (CaI2) and potassium sulfate (K2SO4) are mixed. The reaction that occurs is:
CaI2(aq) + K2SO4(aq) → CaSO4(s) + 2KI(aq)
The solubility product constant for calcium sulfate (CaSO4) is 2.4 x 10^-5. Let x represent the minimum concentration of K2SO4 required to cause precipitation. The concentration of Ca2+ ions in solution is 9.0 x 10^-2 M. The Ksp expression for CaSO4 is:
Ksp = [Ca2+][SO42-]
Substituting the known values gives:
(2.4 x 10^-5) = (9.0 x 10^-2)(x)
Solving for x gives:
x = (2.4 x 10^-5)/(9.0 x 10^-2)
x = 2.67 x 10^-4 M
So, the minimum concentration of K2SO4 required to cause precipitation of CaSO4 is 2.67 x 10^-4 M.
For part b, silver nitrate (AgNO3) and rubidium chloride (RbCl) are mixed. The reaction that occurs is:
AgNO3(aq) + RbCl(aq) → AgCl(s) + RbNO3(aq)
The solubility product constant for silver chloride (AgCl) is 1.77 x 10^-10. Let y represent the minimum concentration of RbCl required to cause precipitation. The concentration of Ag+ ions in solution is 2.0 x 10^-3 M. The Ksp expression for AgCl is:
Ksp = [Ag+][Cl-]
Substituting the known values gives:
(1.77 x 10^-10) = (2.0 x 10^-3)(y)
Solving for y gives:
y = (1.77 x 10^-10)/(2.0 x 10^-3)
y = 8.85 x 10^-8 M
So, the minimum concentration of RbCl required to cause precipitation of AgCl is 8.85 x 10^-8 M.