For the following chemical equation 2 Al (s) + 6 HCl (aq) ----> 2 AlCl3 (aq) + 3H2 (g) How many grams of Al should be mixed with hydrochloric acid to obtain the hydrogen gas conditions of 2.06 L, 301 K

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18 votes

Answer:

Your answer will be 34.5 g

Step-by-step explanation:

The molar mass of aluminum (Al) is 26.98 g/mol. In the formula above, replace the values. This results in 34.5 g of aluminum (Al) being required.

Sashka answered Feb 6, 2023

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