Question

Select the correct answer from the drop-down menu. The design for a two-tank system is shown. The inner tank must be surrounded by oxygen with a density of 0.0827 pounds per cubic foot. Diagram shows a small rectangular prism placed inside a large rectangular prism. Small prism has a length of 5 feet, a width of 4 feet, and a height of 3 feet. Large prism has a length of 20 feet, a width of 8 feet, and a height of 6 feet. What amount of oxygen is needed in the outer tank? To meet the density required, approximately pounds of oxygen is required.

Answer 1

Answer: 74 pounds

Explanation:

(20*8*6) - (5*4*3)

960-60

v=900 ft3

density=0.0827

mass=0.0827*900

Mass is 74 pounds

Answer 2

74.43 pounds

Explanation:

To find the amount of oxygen needed in the outer tank, we need to first find the volume of the space between the two tanks. This space is a rectangular prism with length 20 feet, width 8 feet, and height 6 feet, but with a rectangular prism removed from the center. The removed prism has length 5 feet, width 4 feet, and height 3 feet.

The volume of the rectangular prism between the two tanks is:

V = (20 x 8 x 6) - (5 x 4 x 3)

V = 960 - 60

V = 900 cubic feet

To find the amount of oxygen needed to fill this space with a density of 0.0827 pounds per cubic foot, we can multiply the volume by the density:

m = V x d

m = 900 x 0.0827

m ≈ 74.43 pounds

Therefore, approximately 74.43 pounds of oxygen is required to meet the density requirement.