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Suppose that the microwave radiation has a wavelength of 12.4 cm. How many photons are required to heat 205 mL of coffee from 25.0 ∘C to 62.0 ∘C ? Assume that the coffee has the same density, 0.997 g/mL, and specific heat capacity, 4.184 J/(g⋅K), as water over this temperature range.

User Muichkine
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Answer:

To calculate the number of photons required to heat the coffee, we can follow these steps:

Calculate the mass of the coffee using its volume and density:

mass = volume x density = 205 mL x 0.997 g/mL = 204.185 g

Calculate the amount of heat required to raise the temperature of the coffee using its mass, specific heat capacity, and temperature change:

q = m x c x ΔT = 204.185 g x 4.184 J/(g⋅K) x (62.0 - 25.0) °C = 32289.6 J

Calculate the energy of each photon using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the microwave radiation:

E = (6.626 x 10^-34 J⋅s) x (3.00 x 10^8 m/s) / (0.124 m) = 5.067 x 10^-23 J

Calculate the number of photons required to deliver the amount of energy needed to heat the coffee:

number of photons = q / E = 32289.6 J / 5.067 x 10^-23 J = 6.368 x 10^25 photons

Therefore, approximately 6.368 x 10^25 photons are required to heat 205 mL of coffee from 25.0 ∘C to 62.0 ∘C using microwave radiation with a wavelength of 12.4 cm.

User Ken Burkhardt
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