In triangle ABC, <A and <B are complementary, where cos A=0.68. What is the value of the sine of angle B?

Ermin Dedovic asked Oct 14, 2023

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Ermin Dedovic asked Oct 14, 2023

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15 votes

Answer:

sin B = 0.68

Explanation:

sin(angle) = cos(complement)

since ∠ A and ∠ B are complementary , then

sin B = cos A = 0.68

Evolution answered Oct 21, 2023

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