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7 votes
7 votes
Solve for all possible values of x.

√9x-9 = x + 1

Omg help someone i don’t get this

User Colin Pear
by
2.8k points

1 Answer

15 votes
15 votes

Answer:

x = 2 , x = 5

Explanation:

assuming you mean


√(9x-9) = x + 1 ( square both sides to clear the radical )

(
√(9x-9) )² = (x + 1)² ← expand using FOIL

9x - 9 = x² + 2x + 1 ( subtract 9x from both sides )

- 9 = x² - 7x + 1 ( add 9 to both sides )

0 = x² - 7x + 10 ← factor the quadratic

consider the factors of the constant term (+ 10) which sum to give the coefficient of the x- term (- 7)

the factors are - 2 and - 5 , since

- 2 × - 5 = + 10 and - 2 - 5 = - 7 , then

(x - 2)(x - 5) = 0

equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x - 5 = 0 ⇒ x = 5

As a check

substitute these values into the equation and if both sides are equal then they are the solutions.

x = 2

left side =
√(9(2)- 9) =
√(18-9) =
√(9) = 3

right side = 2 + 1 = 3

left side = right side , so x = 2 is a solution

x = 5

left side =
√(9(5)-9) =
√(45-9) =
√(36) = 6

right side = 5 + 1 = 6

left side = right side, so x = 5 is a solution

User Superbiji
by
3.1k points
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