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A solution of rubbing alcohol is 76.4% (v/v) isopropanol in water. How many milliliters of isopropanol are in 89.6 mL sample of the rubbing alcohol solution?

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Answer:

68.4 mL of isopropanol

Step-by-step explanation:

vol of solute/vol of solution ×100%=76.4% isopropanol

.764×89.6mL = 68.4 mL

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