Question

Write the equation of a line passing through the points (6,8) and (10,10).

1. y = 1/2 x - 5
2. y = 2x - 4
3. y = -1/2 x + 11
4. y = 1/2 x + 5

Answer 1

4

Explanation:

y = mx + b

We need to find the slope (m) and the y-intercept (b)

y = _x + b

Slope:

change in y over the change in x. The y values are 10 and 8. The x values are 10 and 6. We find the change by subtracting.

`(10 - 8)/(10 - 6)` =
`(2)/(4)` =
`(1)/(2)`

The slope (m) is
`(1)/(2)`

y-intercept:

To find this we need the slope
`(1)/(2)` and the x and y from one of the points. I will use the point (6,8) The y value is 8 and the x value is 6

y = mx + b

8 =
`(1)/(2)`(6) + b

8 = 3 + b Subtract 3 from both sides

8 - 3 = 3 -3 +b

5 = b

The y-intercept is 5.

y =
`(1)/(2)` x + 5

Helping in the name of Jesus.