Question

If two parents have the genotypes AA x aa, the probability of having an Aa genotype in the F 2 ​ generation is

Answer 1

When two parents with the genotypes AA x aa reproduce, they will produce offspring with the genotype Aa in the F1 generation.

The F1 generation will then produce gametes (reproductive cells) with one of each parent's alleles (A or a), resulting in the possible gametes of A or a.

When we cross two Aa individuals (the F1 generation), we can use a Punnett square to determine the probabilities of their offspring having different genotypes:

A a
A AA Aa
a Aa aa

In this Punnett square, the possible combinations of gametes are shown along the top and left side. The boxes in the middle show the possible genotypes of the offspring.

From this Punnett square, we can see that there are 4 possible outcomes, with each having a 25% probability:

25% AA (homozygous dominant)
50% Aa (heterozygous)
25% aa (homozygous recessive)
Therefore, the probability of having an Aa genotype in the F2 generation when two parents with the genotypes AA x aa reproduce is 50%.

Answer 2

50%

Step-by-step explanation:

When two parents have the genotypes AA x aa, they are said to be homozygous dominant and homozygous recessive respectively. Their offspring are called the F1 generation, which will all have the genotype Aa because of the law of segregation.

If the F1 generation is allowed to interbreed, their offspring will be the F2 generation. The probability of an F2 offspring having the Aa genotype can be determined using a Punnett square.

First, we need to write out the gametes that each parent can produce:

Parent 1: AA (can produce only A gametes)

Parent 2: aa (can produce only a gametes)

Using these gametes, we can create a Punnett square:

| A | A

--|----|----

a | Aa | Aa

a | Aa | Aa

The four boxes in the Punnett square represent the possible genotypes of the F1 offspring. We repeat this for F2:

| A | a

--|----|----

A | AA | Aa

a | Aa | aa

Therefore, the probability of having an Aa genotype in the F2 generation when two parents have the genotypes AA x aa is 0.5 (or 50%).