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The temperature of a 77.0 g sample of material increases from 15.0◦C to 49.0◦C when it

absorbs 4.00 kJ of energy as heat. What is
the specific heat of this material?

User Danthar
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1 Answer

2 votes

Answer:

We can use the formula for heat transfer to calculate the specific heat of the material:Q = mCΔTwhere Q is the amount of heat transferred, m is the mass of the material, C is the specific heat of the material, and ΔT is the change in temperature.We are given the mass of the material (m = 77.0 g), the initial temperature (T1 = 15.0◦C), the final temperature (T2 = 49.0◦C), and the amount of heat transferred (Q = 4.00 kJ = 4000 J).First, we need to calculate the change in temperature:ΔT = T2 - T1 = 49.0◦C - 15.0◦C = 34.0◦CSubstituting the given values into the formula, we get:4000 J = 77.0 g x C x 34.0◦CSimplifying and solving for C, we get:C = 4000 J / (77.0 g x 34.0◦C) = 1.71 J/g◦CTherefore, the specific heat of the material is 1.71 J/g◦C.

User Matt Fordham
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