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Assume that a researcher randomly selects 14 newborn babies and counts the number of girls selected, x. The probabilities corresponding to the 14 possible values of x are summarized in the given table. Find the probability of selecting 2 or more girls.

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Answer: 0.953

Explanation:

Since we are interested in the probability of selecting 2 or more girls, we need to add up the probabilities corresponding to the values of x that satisfy this condition.

The values of x that correspond to selecting 2 or more girls are 2, 3, 4, ..., 14.

So, we need to add the probabilities of these values:

P(X >= 2) = P(X=2) + P(X=3) + ... + P(X=14)

Using the given table, we can find the probabilities for each of these values:

P(X=2) = 0.277

P(X=3) = 0.393

P(X=4) = 0.259

P(X=5) = 0.098

P(X=6) = 0.023

P(X=7) = 0.003

P(X=8) = 0.000

The sum of these probabilities is:

P(X >= 2) = 0.277 + 0.393 + 0.259 + 0.098 + 0.023 + 0.003 + 0.000

P(X >= 2) = 0.953

Therefore, the probability of selecting 2 or more girls is approximately 0.953.

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